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In Reply to: Re: The sine vs. saw tooth wave is an excellent test. posted by jsm on January 26, 2006 at 12:47:59:
sorry! i was preparing to do the test, then i realised i can't do justice to the test :-(in terms of two samples to define a sine wave - this can be mathematically proven and indeed is a basis of sampling theorem. however, you are right - both samples right on the zero crossing is a "pathological" exception.
that's why sampling theorem says you can reproduce all sine waves up to (but not including) the Nyquist frequency.
eg. if the sampling rate is 48kHz, you can reproduce all frequencies up to 23.9999... kHz but not including 24 kHz for the precise reason that the samples could fall right on the zero crosses.
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Follow Ups
- Re: The sine vs. saw tooth wave is an excellent test. - Christine Tham 14:27:01 01/26/06 (0)
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