In Reply to: I guess I will have to quit posted by tunenut on October 25, 2006 at 21:27:20:
Here's the table you are looking for -where R = revealed door
door1 door2 door3
win loseR lose
win lose loseRlose winR lose
lose win loseRlose lose winR
lose loseR winLet's look at randomly revealing a door per our example. The possibilities are
loseR2 loseR3 (this row represents what's missing from your POV)
winR2 loseR3
loseR2 winR3Clearly there is only a one in 6 chance that the winning door is revealed. And since we know that there is a 1/3 chance that door #1 is a winner then 1-1/6-1/3=1/2 gives the odds of winning if we switch.
I have given you all 6 possibilities that can happen.
I guess it depends one how you want to define possibilities but this conversation is about odds and chance which may be quite different than possibilities.
In your table to fail to account for the fact that only door 2 and door 3 can be randomly revealed. But the truth of matter is that 1/3 of the time door #1 is going to win and we need to take that into account.
Give me rhythm or give me death!
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Follow Ups
- Re: I guess I will have to quit - Don T 00:20:28 10/26/06 (12)
- Re: I guess I will have to quit - tunenut 07:19:05 10/26/06 (11)
- Re: I guess I will have to quit - Don T 11:56:28 10/26/06 (2)
- Re: I guess I will have to quit - tunenut 18:20:39 10/26/06 (1)
- Re: I guess I will have to quit - Don T 23:12:00 10/26/06 (0)
- Re: I guess I will have to quit - Don T 08:25:01 10/26/06 (7)
- here is your logical fallacy - tunenut 10:07:27 10/26/06 (6)
- It's still wrong. - Don T 11:41:47 10/26/06 (5)
- Please answer my three questions (NT) - tunenut 11:44:56 10/26/06 (4)
- Re: Please answer my three questions (NT) - Don T 12:04:12 10/26/06 (3)
- Re: Please answer my three questions (NT) - tunenut 12:45:51 10/26/06 (2)