In Reply to: Your load resistor posted by Jacques on September 8, 2006 at 01:07:43:
I used two pieces of a 3/4 dia copper pipe, and soldered 38 resistors in a cylindrical configuration between the two pipes. In between the resistors, I soldered wires going the other way, and at the last moment, before the wires shorted the resistors out, bent the wires in, towards another copper pipe of slightly smaller diameter.This provides a coaxial structure for powering the resistor.
By alternating current direction, the magnetic field outside the resistor will drop off as 1/R 19, and internally as 1/R 18.
While the calculated inductance is indeed 60 picohenries, it is not physically possible to measure this via the coaxial structure, this being due to the current dispersion paths before pure coaxial currents are established, that takes several tube diameters in length to form that.. The best I have been able to do so far, is measure it repeatably to less than 250 picohenries at 100 Khz. The v tap wire embedded allows better measurement, but that requires equipment I do not have access to.
I posted pics over at diy previously and will look for them, and have a full build sequence on disk here, which I can make available if you wish.
Cheers, John
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Follow Ups
- Sure - jneutron 06:53:50 09/08/06 (3)
- If you have the build sequence - Jacques 07:52:02 09/08/06 (2)
- Picture 8 did not make it, the message did not state why. - jneutron 11:41:20 09/08/06 (0)
- Got pics of the whole shebang - jneutron 09:05:00 09/08/06 (0)