In Reply to: Re: Well, actually, a fourier transform HAS to be able to detect them all... posted by jneutron on June 15, 2006 at 13:08:47:
The energy disappated is not (a+b)^2, a and b, having different frequency content, are orthogonal, and add as squares, not as amplitude, so in fact there is no problem here.This is a classic linear-systems problem.
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Follow Ups
- Ahh, I see what you mean... there's a math error. - real_jj 13:41:14 06/15/06 (5)
- Re: Ahh, I see what you mean... there's a math error. - jneutron 14:02:41 06/15/06 (4)
- Yes, but you're missing the point.... - real_jj 14:30:30 06/15/06 (3)
- Actually, it's far more interesting than that - jneutron 06:23:52 06/16/06 (2)
- Well, I can only suggest that you look at each waveform in a simulation... - real_jj 14:22:56 06/16/06 (1)
- been there, done that. - jneutron 05:49:18 06/19/06 (0)