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Propeller Head Plaza Technical and scientific discussion of amps, cables and other topics. |
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Propeller Head Plaza Technical and scientific discussion of amps, cables and other topics. |
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In Reply to: Question for jneutron re analysis posted by Commuteman on January 13, 2004 at 17:14:12:
"If the cable is, say, 8mm in diameter and 1m long, it has a surface area of about 2.5E-2 m2. This is approximately 6280 times bigger than Bruce's fingernail contact patch.This means that the same energy could be produced by a pressure change that is 1/6280 of the pressure exerted by Bruce's finger. "
Interesting, first off, the trick would be actually deforming the entire surface. The simple force division doesn't hold. An example would be using a nail and applying an increasing amount of force to the head until the point deforms the surface of a piece of wood, then taking the hammer head and applying that same force to find nothing happens. I think what you're looking for is a force measured in units per surface area instead of a particular force.
Acoustically I think you'd have a better chance of causing the cable to bend before deforming the entire surface, so any output you'd see would be the result of the cable bending moment near the two attachment points.
-Bruce
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Follow Ups
- Re: Question for jneutron re analysis - FLZapped 10:00:03 01/14/04 (6)
- Re: Question for jneutron re analysis - jneutron 12:05:45 01/14/04 (0)
- Force per unit area is called "pressure" - Commuteman 11:54:15 01/14/04 (4)
- Re: Force per unit area is called "pressure" - FLZapped 14:06:19 01/14/04 (0)
- Re: Force per unit area is called "pressure" - jneutron 12:20:05 01/14/04 (2)
- Re: Force per unit area is called "pressure" - FLZapped 14:14:36 01/14/04 (1)
- Re: Force per unit area is called "pressure" - jneutron 08:14:06 01/15/04 (0)
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