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Ah, that is what I thought.

I did indeed do a google search, and I did get the material you have pointed out..I was hoping you had something different...something which supported your assertion of "zero noise nanotube resistors", as the article by Stefan Frank, Philippe Poncharal, Z.L. Wang, and Walt A. de Heer does not support noiseless resistance, but they did good work on quantized conductance..

Note on the first page, the text on the bottom of the first column...
(wish it weren't pdf, it'd save me typing)

Quoted from Science, vol 280, page 1744... : ""Another important aspect of ballistic transport is that no energy is dissipated in the conductor.(20). Instead, the Joule heat is dissipated in the electrical leads, which connect the ballistic conductor to the macroscopic elements of the circuit.""


As they said, they are showing quantized conductance..and by virtue of ballistic transport, the electrons are travelling without hitting anything..HOWEVER, they state that the energy that the electron ends up with at the end of their travel within the nanotube is dissipated as Joule heat when it gets to the end of the resistor..

In other words, they simply moved all the noise generation from the tube itself, to the end terminals.

If you go to the bottom left of page 1746, you see their discussion on the power dissipation of the nanotube with current densities on the order of 107 amps/cm2, vs superconductors capacity of 105 amps/cm2 (what I do for a living), the dissipation of 3mW, and why the transport is ballistic, and the end terminals do all the "noisin and heatin"....


Thanks, cheers, John




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