In Reply to: Re: Are they both consuming energy? posted by jneutron on September 4, 2003 at 06:44:47:
This is a fascinating discussion; I'm actually being forced to exercise the gray matter (and boy, is it out of shape....)So....
The Seebeck and Peltier effects exist because of a potential difference due to the different forces on the free electrons in the two materials. This creates an electric field at the boundary. Electrons near the junction experience asymmetrical forces due to the difference in the materials, so they migrate (Seebeck) or they gain or lose energy as they are pushed across the junction (Peltier).
Have I got that right?
To me, this suggests that the current through the junction is unaffected in our scenario, but there is a voltage step as electrons pass from one material to the other. Heating or cooling depends on whether the electrons are moving up or down the electric field created at the material boundary. Doesn't this also mean that the heat produced or consumed is equal to the delta V times current? In other words, delta V = Watts/Amps (which is also the delta of the Peliter coeffs). Note that it appears to be area independent...
If the junctions are identical, how is the energy gained by an electron at one junction not exactly the same as the energy lost by that electron at the opposite junction? (yeah, yeah, I know the electrons arent drifting at signal propafation speeds, but throw me a friggin bone, here...)
I guess I'm not tracking with your comment that there is a mechanism whereby the heat is dragged along the wire.
If there is such a mechanism, then isn't it something different from the Peltier effect per se?
OK, time for a nap.....
Peter
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Follow Ups
- Not so fast buddy..... - Commuteman 15:44:25 09/04/03 (3)
- Re: Not so fast buddy..... - jneutron 05:59:31 09/05/03 (2)
- I'm glad I'm not lifting that sheetrock, although we do need to do that kitchen... - Commuteman 09:39:05 09/05/03 (1)
- I couldn't afford the money I'd want to charge to do this stuff. - jneutron 10:18:06 09/05/03 (0)