In Reply to: Hmmm. posted by jneutron on August 27, 2003 at 10:19:56:
The seebeck returns would also be antisymmetrical, so both ends of your cable should cancel out....VOLTAGE wise..Of concern is the energy loss with time..That is a function of the current waveform..as in, the energy sent into supporting the thermal gradient does not necessarily get pulled from the signal as a function of the sine..but, more a very complex function including peltier coeff, peltier eff, delta T, heat capacity, conductivity.
That's why I switched to energy calculations for the other analysis'. It is easier to consider that way. I don't know how I'd model the rather complex function with all those elements yet.
I have done so by using a recursive computer program. Ran an analysis on a #26 awg copper wire with a 200 amp, 100ms RC pulse starting at 4.5K, to determine temp rise..Got some really good results. Then my co-author took all my recursive equations, turned then into classical functions, and tossed them into an excel program. Not an easy feat, as copper heat capacity is a huge function of temperature. Made me feel about 3 inches tall....big time humble pie...
Further down the road, if we really think this is worth pursuing, maybe I can start doing another program..I'd use a step junction, and break the volume into thin slabs, then do a time recursion thingy.
Major fun, Peter..pleasure's mine
Cheers, John
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Follow Ups
- double hmmmm. - jneutron 10:36:37 08/27/03 (0)