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Tube DIY Asylum Do It Yourself (DIY) paradise for tube and SET project builders. |
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Tube DIY Asylum Do It Yourself (DIY) paradise for tube and SET project builders. |
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In Reply to: capacitance presented to source with input splitter transformer? posted by Joel Tunnah on September 23, 2005 at 09:48:22:
The input capacitances of the two differential tubes (each tube's Miller C plus Cgk) is seen by the transformer as being in series, not parallel. Therefore you divide 120pF or so by two and that's what the total secondary sees, and what is reflected 1:1 into the primary circuit. This is sometimes a tough concept to grasp. But with transformers, you have additonal stray capacitance and leakage inductance, so what is seen at the input of the amp will be more complex than just 60pF. Morgan Jones has a decent section in his book on differential input capacitance as seen by/through a transformer.
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Follow Ups
- No, divide by two - BBeck 11:27:46 09/23/05 (6)
- Found it in the Jones book, like you said. Thanks. (nt) - Joel Tunnah 19:01:42 09/23/05 (2)
- What page?(nt) - Russ57 08:52:27 09/27/05 (1)
- Re: What page?(nt) - BBeck 07:35:07 09/29/05 (0)
- Time to eat crow...and a question - Russ57 14:28:56 09/23/05 (2)
- Capacitance-inductance transform - marnold 17:19:03 09/24/05 (0)
- Re: Time to eat crow...and a question - BBeck 14:35:39 09/23/05 (0)
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