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In Reply to: Help with math... posted by Nickel Core on July 13, 2006 at 05:01:00:
well, IF "I = X times Y to the Z power" is what you mean, solve for Z.
I am taxing my memory here, but I am sure I'll be corrected if I am wrong!1) divide both sides by X:
I/X = Y^Z
2) take the log (any flavor of log you like; I like base 10) of both sides to get rid of that nasty exponent:
log (I/X) = log (Y^Z)
log (I/X) = log Y * log Z
[log (I/X) = log I - log X, FWIW]
3) solve for Z
log Z = (log (I/X))/log Y
Z = 10^[log (I/X)/log Y]
I think.
all the best,
mrh
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Follow Ups
- umm... - mhardy6647 06:53:07 07/13/06 (4)
- Sorry, that isn't right. - Tutordennis 10:06:04 07/13/06 (2)
- yeah, I realized my error 'logging' Y^Z - mhardy6647 12:14:30 07/13/06 (0)
- Thanks, according my spreadsheet that is right! (nt) - Nickel Core 10:33:27 07/13/06 (0)
- Thanks! (I think..) - Nickel Core 07:35:11 07/13/06 (0)
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