The following web site describes a circuit that utilizes a 6201 twin triode for common grid IV conversion:http://ultranalog.com/cdenhancer/cdenhancer1.html
(please see figure 2)
The DAC appears to be connected to the analog circuit using a 1 volt source between the digital ground and analog ground, the idea being that the DAC sees 0V.
But what is this 1V source? It appears to be a battery symbol, but I don't believe the circuit would function with a battery connecting the analog to digital ground.
Can someone please elaborate on what this voltage source might be?
Thanks!
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Topic - Common Grid IV Conversion - Circut Help Needed - kblsnbts 05:28:33 07/11/06 (8)
- Re: Common Grid IV Conversion - Circut Help Needed - Dave Davenport 08:42:23 07/11/06 (1)
- EXACTLY!!!!! - Allen Wright 04:30:05 07/12/06 (0)
- What I have experiemented with - Gordon Rankin 07:03:36 07/11/06 (5)
- Conceptual mistake, Gordon. - Allen Wright 04:35:53 07/12/06 (4)
- Mistake? - Gordon Rankin 07:17:30 07/12/06 (3)
- My question is why even use feedback? - Allen Wright 00:47:09 07/13/06 (0)
- Re: Mistake? - BBeck 11:05:47 07/12/06 (1)
- Sorry, link now attached - BBeck 11:08:14 07/12/06 (0)