To reflect on Cable Capacitance

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OTL, Output Transformerless Amplifier User Group.

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Lets say a cable offers a capacitance of 1.5nf/ft .
So a ten foot run would have 15nf (or 0.015uf) of capacitance . ( yes this a snippet from a post )
Question is , if treated as normal capacitance , where ' series-ed ' capacitance is not added as above in the example . IF for example I had two lengths of the above 10 ft spans , and connected them together , why would I not measure 1 / ( 1/15 + 1/15 )= 7.5nf ?
What am I missing here , is it the return path that creates the parallel effect so adding capacitance by usual methods ie ( 15nf + 15nf = 30nf ) becomes the correct answer ???
As my theory on paper means that if you had a 10 ft span of 1.5nf / ft it should equal 0.15nf/ 10 ft !
Im confused at what you would measure , as I dont have my LCR meter on hand at present to test this in practice . Please shed light .
Thanks Stu

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Topic - To reflect on Cable Capacitance - stu 21:26:27 01/13/03 (2)

Re: To reflect on Cable Capacitance - Al Sekela 10:49:30 01/14/03 (0)

Re: To reflect on Cable Capacitance - Neal Hood 03:56:05 01/14/03 (0)

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